All labs 05

Quantum Teleportation Protocol

Advanced quantum

Alice’s state ∣ψ⟩|\psi\rangle is parameterised on the Bloch angles. Stepped playback advances the register through entanglement, Bell measurement, and the classically controlled Xm2/Zm1X^{m_2}/Z^{m_1} corrections; hovering any gate reveals its action in Dirac notation.

Live circuit step 1 of 6, initialize
Quantum Teleportation Protocol12 components and 11 connections.PSI|ψ⟩A|0⟩B|0⟩HH1HCX1CNOTCX2CNOTHH2HMZ1MZMZ2MZXm2XCXm2Zm1ZCZm1OUT|ψ⟩
Quantum Teleportation Protocol

Drag θ and φ on the input state. Hover a gate for its action; click one to read it.

∣ψ⟩=0.000∣0⟩+(0.000 + 0.000i)∣1⟩\lvert\psi\rangle=\htmlData{math-slot=alpha}{\mathtt{0.000}}\lvert0\rangle+\left(\htmlData{math-slot=beta}{\text{0.000 + 0.000i}}\right)\lvert1\rangle

Protocol playback

  1. initialize
  2. entangle A↔B
  3. Bell-basis rotation
  4. measure classical bits
  5. apply Pauli corrections
  6. state reconstructed

Quantum-state phasor animation running.

Fault injection

Causal signal trace paused

Prepare ψ\psi and ancillas The unknown state and two ∣0⟩\lvert 0\rangle ancillas enter on separate rails.

Step 1 / 6 Prepare ψ and ancillas

Notebook: 12 parts and 11 wires, modelled as stepped three-qubit protocol

Recommended lab 5 of 18

Explain why entanglement and two classical bits are both necessary for teleportation.

Builds on: Bell-State Entanglement Visualizer

Predict, then test

Alice completes her Bell measurement but Bob receives no correction bits. What happens to fidelity?

Commit before the explanation appears. This is a prediction, not a quiz score.

Governing model
∣ψ⟩=α∣0⟩+β∣1⟩  ⋅  α=cos⁡θ2, β=eiϕsin⁡θ2|\psi\rangle = \alpha|0\rangle + \beta|1\rangle \;\cdot\; \alpha = \cos\tfrac{\theta}{2},\ \beta = e^{i\phi}\sin\tfrac{\theta}{2}
Parts
  • 3×3\times qubit trace (ψ,A,B)(\psi,A,B)
  • HH + CNOT preparation
  • Bell-basis measurement
  • X/ZX/Z correction gates
Limits of the model
  • Bloch θ∈[0,π], ϕ∈[0,2π]\theta\in[0,\pi],\ \phi\in[0,2\pi]
  • 66-step protocol
  • fidelity F=∣⟨ψ∣ψout⟩∣2F=|\langle\psi|\psi_{out}\rangle|^2
Diagnosis challenge The fault is hidden. Work it out from the changed outputs first.